parse a type to a function
Posted: Fri Mar 10, 2006 7:02 am
Can I parse for example:
grtz
Seb
Code: Select all
DECLARE FUNCTION CheckType (ctype)
TYPE sumfin
x AS INTEGER
y AS INTEGER
c AS INTEGER
t AS STRING
END TYPE
DIM SHARED wins AS sumfin
wins.x = 0:wins.y = 10: wins.c = 2: t = "dull!"
parsed = CheckType(wins)
IF PARSED = 1 THEN
PRINT "Okay"
ELSE
PRINT "Not okay." 'Duh!!
END IF
FUNCTION CheckType (ctype)
IF ctype.x > 0 AND ctype.x < 20 THEN
IF ctype.y > 0 AND ctype.y < 20 THEN
IF ctype.c > 0 AND ctype.c <= 15 THEN
IF ctype.t <> "" THEN
CheckType = 1
EXIT FUNCTION
ELSE
CheckType =0
END IF
ELSE
CheckType = 0
END IF
ELSE
Checktype = 0
END IF
ELSE
CheckType = 0
END IF
END FUNCTION
Seb