Pete's QBASIC Site

x + x^2=90

2007-01-27T12:47:16-05:00

Yes, I think the quadratic formula would be the best way to solve it, since it works for ANY quadratic.

Code:

PosX=(-B+SQR((B^2)-(4*A*C)))/(2*A)NegX=(-B-SQR((B^2)-(4*A*C)))/(2*A)

as the quadratic formula has a plus and minus. However, if the discriminant (B^2-4AC) is negative, QB will generate an error because it has an imaginary solution.

Statistics: Posted by Patz QuickBASIC Creations — Sat Jan 27, 2007 12:47 pm

x + x^2=90

2007-01-25T20:05:58-05:00

Nathan, I don't remember how to solve it either, but I don't thing the quadratic equation is going to help.

Yoo could use the brute force approach by writing a little program that uses a FOR loop on X, and keeps testing until it finds it. Something like this:
[code}
FOR X = 1 TO 90
T = X + X^2
IF T = 90 THEN PRINT "ANSWER = ";X : GOTIT=1 :EXIT FOR
NEXT X
IF GOTIT=0 THEN PRINT "NOT FOUND, X MUST BE FRACTIONAL"
[/code]

PS, I haven't tried it.

Regards..... Moneo

Statistics: Posted by moneo — Thu Jan 25, 2007 8:05 pm

Re: x + x^2=90

2007-01-25T17:50:52-05:00

I know that in this case, x is equal to 9, but how would I figure this out mathematically?

Looks like you have a quadratic equation thingy.

x^2 + x - 90 = 0

though that could be optimized a bit because 'a' and 'b' would be ones.

Statistics: Posted by seaBiscuit$ — Thu Jan 25, 2007 5:50 pm

x + x^2=90

2007-01-25T17:16:43-05:00

I know that in this case, x is equal to 9, but how would I figure this out mathematically?

Statistics: Posted by {Nathan} — Thu Jan 25, 2007 5:16 pm